Mass Transfer B K Dutta Solutions May 2026

A droplet of liquid A is suspended in a gas B. The diameter of the droplet is 1 mm, and the diffusivity of A in B is 10^(-5) m²/s. If the droplet is stationary and the surrounding gas is moving with a velocity of 1 m/s, calculate the mass transfer coefficient.

Mass Transfer B K Dutta Solutions: A Comprehensive Guide** Mass Transfer B K Dutta Solutions

\[N_A = rac{10^{-6} mol/m²·s·atm}{0.1 imes 10^{-3} m}(2 - 1) atm = 10^{-2} mol/m²·s\] A droplet of liquid A is suspended in a gas B

A mixture of two gases, A and B, is separated by a membrane that is permeable to gas A but not to gas B. The partial pressure of gas A on one side of the membrane is 2 atm, and on the other side, it is 1 atm. If the membrane thickness is 0.1 mm and the permeability of the membrane to gas A is 10^(-6) mol/m²·s·atm, calculate the molar flux of gas A through the membrane. Mass Transfer B K Dutta Solutions: A Comprehensive

Substituting the given values:

where \(N_A\) is the molar flux of gas A, \(P\) is the permeability of the membrane, \(l\) is the membrane thickness, and \(p_{A1}\) and \(p_{A2}\) are the partial pressures of gas A on either side of the membrane.