θ = D 2.44 λ
But we have
where \(D\) is the distance between the transmitter and receiver. exercice corrige faisceaux hertziens pdf
Using the formula for the beamwidth of a Faisceau Hertzien: θ = D 2
d = D × 1 0 20 L
Rearranging the formula to solve for \(d\) : exercice corrige faisceaux hertziens pdf